1x^2+7x-256=0

Solution for 1x^2+7x-256=0 equation:

1x^2+7x-256=0

We add all the numbers together, and all the variables

x^2+7x-256=0

a = 1; b = 7; c = -256;
Δ = b2-4ac
Δ = 72-4·1·(-256)
Δ = 1073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1073}}{2*1}=\frac{-7-\sqrt{1073}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1073}}{2*1}=\frac{-7+\sqrt{1073}}{2}
$